CBSE Class 10 Science 2026: question 36
Set in the CBSE Class 10 board exam of 2026, paper 31/5/1, section C, question 36, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q36 · 3 marks · Short answerLight – Reflection and Refraction
(a) A ray of light after reflection from a concave mirror becomes parallel to its principal axis. Draw a labelled ray diagram to show this.
(b) (i) Differentiate between the virtual images formed by a convex mirror and concave mirror.
(ii) "The value of magnification 'm' for a mirror is –2." Calculate the height of object if the height of image is 20 cm.
- (a)0 marks
A ray of light after reflection from a concave mirror becomes parallel to its principal axis. Draw a labelled ray diagram to show this.
- (b)(i)0 marks
Differentiate between the virtual images formed by a convex mirror and concave mirror.
- (b)(ii)0 marks
"The value of magnification 'm' for a mirror is –2." Calculate the height of object if the height of image is 20 cm.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 31/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Which special point must a ray pass through so that after reflection it goes parallel to the axis?
Hint 2
Compare the size of virtual images in the two mirrors.
Hint 3
Magnification = image height ÷ object height; a negative m means an inverted image.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(a) Draw a concave mirror with pole , principal focus and centre of curvature on the principal axis. Draw a ray from the object passing through (or directed from) towards the mirror; after reflection it travels parallel to the principal axis. Show arrows on both rays and label , , and the principal axis.
- 1 mark
(b)(i) Virtual image by a convex mirror is always diminished and is formed for all positions of the object; virtual image by a concave mirror is enlarged and is formed only when the object lies between and .
- ½ mark
(b)(ii) ; image is inverted (since is negative), so cm.
- ½ mark
cm. Height of object = 10 cm.
Answer: (b)(i) Convex: diminished, for all positions; concave: enlarged, only when object between P and F; (b)(ii) h = 10 cm
Where the marks are
- Correct labelled ray diagram: ray through F reflects parallel to axis (1 mark)
- Any one correct difference between virtual images (1 mark)
- Uses with cm (½ mark)
- Obtains cm (½ mark)
Revise the chapter
- Chapter: Light – Reflection and Refraction (notes, formulas, where marks are lost and every past question)
- Topic: Lens Formula, Magnification and Power of a Lens
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.