CBSE Class 10 Science 2026: question 39(b)
Set in the CBSE Class 10 board exam of 2026, paper 31/1/1, section C, question 39(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q39(b) · 5 marks · Long answerElectricity
Answer the following.
- (i)0 marks
How many bulbs of resistance 8 each should be connected in parallel combination to draw a current of 2 A from a battery of 4 V?
- (ii)0 marks
Name the device used for measuring electric current. How is it connected in a circuit?
- (iii)0 marks
State Joule's law of heating.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 31/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
First find the total resistance the circuit must have to draw 2 A from 4 V.
Hint 2
For n equal resistors R₀ in parallel, the equivalent resistance is R₀/n.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
(i) Required total resistance: .
- ½ mark
(i) .
- ½ mark
(i) Let bulbs of be joined in parallel. Then ( terms) .
- ½ mark
(i) , so . 4 bulbs should be connected in parallel.
- 1 mark
(ii) The device used for measuring electric current is an ammeter.
- 1 mark
(ii) It is always connected in series in the circuit.
- 1 mark
(iii) Joule's law of heating: the heat produced in a resistor is directly proportional to the square of the current, to the resistance, and to the time for which the current flows. So .
Answer: (i) 4 bulbs; (ii) ammeter, connected in series; (iii) H = I²Rt (heat ∝ I², R and t)
Where the marks are
- (i) Uses (½ mark)
- (i) Gets (½ mark)
- (i) Parallel relation (½ mark)
- (i) bulbs (½ mark)
- (ii) Ammeter (1 mark)
- (ii) Connected in series (1 mark)
- (iii) Correct statement of Joule's law / (1 mark)
Revise the chapter
- Chapter: Electricity (notes, formulas, where marks are lost and every past question)
- Topic: Resistors in Series and Parallel
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