CBSE Class 10 Science sample paper 2026-27: question 15
From the official CBSE sample question paper for 2026-27, section A, question 15, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q15 · 4 marks · Long answerCompetency-basedHeredity
In order to study patterns of inheritance, Neha had performed typical Mendelian experiments with pea plants in the field. In experiment one, she crossed a pea plant having white flowers (vv) with another pea plant bearing violet flowers (VV). In another experiment, in addition to the colour of the flower she also focussed on the height of the pea plant. This time she crossed a pea plant having violet flowers and tall height (VVTT) with another pea plant having white flowers and short height (vvtt). What percentage is expected for the following traits as a result of these experiments? Give a reason.
- A1 mark
Violet flowers in F1 and F2 generation in experiment one?
- B1 mark
Tall height plants with white flowers in F2 generation in experiment two?
- C0 marks
Attempt either sub-part C or D. Percentage of medium height plants with light violet flowers in F1 and F2 generations in experiment two? Give a reason.
OR
D2 marksPercentage of short height plants with white flowers in F1 and F2 generations in experiment two?
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.
Hints
Open one hint at a time and try again before the next.
Hint 1
Write the F1 genotype first, then self it.
Hint 2
For two traits, multiply the separate probabilities, e.g. P(vv) × P(T_).
Hint 3
Does Mendel's pea plant ever show a 'half-way' trait?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
A. Cross: . All gametes are and , so all F1 plants are . Violet is dominant, so 100% violet in F1.
- ½ mark
F1 selfed: . Violet plants , so 75% violet in F2, because a single dominant gives violet colour.
- 1 mark
B. Cross: F1 all . Selfing F1 gives the dihybrid ratio 9 : 3 : 3 : 1. Tall white plants have genotype or : = 18.75%. This is a combination of one recessive and one dominant trait.
C. (alternative to D, carries 2 marks if attempted instead): 0% in both F1 and F2. In pea plants these traits show complete dominance. A single or gives the same effect as two copies, so no blending or intermediate (medium height, light violet) plants are produced.
- 1 mark
D. F1: all plants are , showing only dominant traits (violet, tall). So short plants with white flowers = 0%.
- 1 mark
F2: short white plants must be double recessive : = 6.25%.
Answer: A. F1 100%, F2 75% violet; B. 3/16 = 18.75%; C. 0% in F1 and F2 (no intermediate traits, complete dominance); D. F1 0%, F2 1/16 = 6.25%.
Where the marks are
- F1 100% and F2 75% violet with dominance reason (1 mark)
- Tall white = 3/16 or 18.75% (1 mark)
- C: 0% in both generations because no intermediate (blended) traits form (2 marks), OR
- D: F1 0% since only dominant traits appear (1 mark); F2 1/16 or 6.25% as vvtt (1 mark)
Revise the chapter
- Chapter: Heredity (notes, formulas, where marks are lost and every past question)
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