CBSE Class 10 Science 2025: question 15
Set in the CBSE Class 10 board exam of 2025, paper 31/2/1, section A, question 15, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q15 · 1 mark · MCQElectricity
Four identical resistors of each are connected in series to form a square ABCD as shown in the figure. The resistance of the network between the two points 1 and 2 is :
- (A)
- (B)
- (C)
- (D)
Figure in the paper: A square loop of four resistors with corners A (top-left), B (top-right), D (bottom-right) and C (bottom-left). Terminal 1 is connected to corner A from above and terminal 2 is connected to corner B from above. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 31/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Trace the two different routes from A to B.
Hint 2
Combine the two routes using the parallel formula.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Points 1 and 2 are joined to the adjacent corners A and B. Between A and B there are two paths:
- the single resistor AB:
- the path A–C–D–B:
These two paths are in parallel:
- 1 mark
Answer: **(C) **.
Answer: , option (C)
Where the marks are
- Finds the and paths in parallel and gets , option (C) (1 mark)
Revise the chapter
- Chapter: Electricity (notes, formulas, where marks are lost and every past question)
- Topic: Resistors in Series and Parallel
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.