CBSE Class 10 Science 2024: question 33
Set in the CBSE Class 10 board exam of 2024, paper 31/3/1, section C, question 33, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q33 · 3 marks · Short answerElectricity
Answer the following.
- (a)0 marks
State Ohm's law. Write formula for the equivalent resistance of the parallel combination of three resistors of values , and .
- (b)0 marks
Find the resistance of the following network of resistors :
Figure in the paper: Resistor network between terminals X and Y: a resistor R in series from X, followed by two resistors R connected in parallel (one on the upper branch and one on the lower branch), then a wire to terminal Y. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 31/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Ohm's law relates V and I under one condition: which one?
Hint 2
First combine the two parallel resistors, then add the series one.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(a) Ohm's law: The potential difference across the ends of a metallic conductor is directly proportional to the current through it, provided its temperature stays the same. So , i.e. .
- 1 mark
(a) Parallel combination:
- 1 mark
(b) Parallel pair: The two resistors in parallel give , so . This combination is in series with the first . Hence .
Answer: (a) V ∝ I at constant temperature; 1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃. (b) Equivalent resistance = 3R/2.
Where the marks are
- Correct statement of Ohm's law including the constant-temperature condition (1 mark)
- Correct parallel formula (1 mark)
- Equivalent resistance R + R/2 = 3R/2 (1 mark)
Revise the chapter
- Chapter: Electricity (notes, formulas, where marks are lost and every past question)
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