CBSE Class 10 Science 2023: question 37
Set in the CBSE Class 10 board exam of 2023, paper 31/4/1, section E, question 37, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q37 · 4 marks · Case-basedCompetency-basedMetals and Non-metals
The melting points and boiling points of some ionic compounds are given below :
| Compound | Melting Point (K) | Boiling Point (K) |
|---|---|---|
| NaCl | 1074 | 1686 |
| LiCl | 887 | 1600 |
| CaCl_2 | 1045 | 1900 |
| CaO | 2850 | 3120 |
| MgCl_2 | 981 | 1685 |
These compounds are termed ionic because they are formed by the transfer of electrons from a metal to a non-metal. The electron transfer in such compounds is controlled by the electronic configuration of the elements involved. Every element tends to attain a completely filled valence shell of its nearest noble gas or a stable octet.
- (i)1 mark
Show the electron transfer in the formation of magnesium chloride.
- (ii)1 mark
List two properties of ionic compounds other than their high melting and boiling points.
- (iii)(A)2 marks
While forming an ionic compound say sodium chloride how does sodium atom attain its stable configuration ?
OR
(iii)(B)2 marksGive reasons : (i) Why do ionic compounds in the solid state not conduct electricity ? (ii) What happens at the cathode when electricity is passed through an aqueous solution of sodium chloride ?
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 31/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Write the electronic configurations of Mg (12) and Cl (17) first.
Hint 2
Think of solubility, hardness and conduction in different states.
Hint 3
Count sodium's valence electrons. Is it easier to lose one or gain seven?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) Mg (2,8,2) loses its two valence electrons, one to each of two Cl atoms (2,8,7): . This gives (2,8) and two (2,8,8) ions.
- ½ mark
(ii) Ionic compounds are hard, brittle solids, and they are generally soluble in water but insoluble in solvents like kerosene and petrol.
- ½ mark
They also conduct electricity in the molten state or in aqueous solution.
- 1 mark
(iii)(A) Sodium (atomic number 11) has the configuration 2,8,1, so it has only one electron in its outermost shell.
- 1 mark
It loses this one electron to chlorine and forms with configuration 2,8: . This is the stable octet of its nearest noble gas, neon.
- 1 mark
(iii)(B)(i) In the solid state the ions are held tightly in a rigid crystal structure and cannot move. Without mobile ions, no current can flow.
- 1 mark
(iii)(B)(ii) Hydrogen gas is liberated at the cathode (sodium hydroxide forms near it, as in the chlor-alkali process).
Answer: (i) Mg → Mg²⁺ + 2e⁻, with each Cl gaining 1e⁻ to form Cl⁻, giving Mg²⁺(Cl⁻)₂; (ii) hard solids, soluble in water, conduct when molten/aqueous (any two); (iii)(A) Na (2,8,1) loses 1e⁻ to form Na⁺ (2,8), the neon configuration; (iii)(B) ions are immobile in the rigid solid; H₂ gas is evolved at the cathode
Where the marks are
- Shows the transfer of two electrons from Mg to two Cl atoms forming Mg²⁺ and 2Cl⁻ (1 mark)
- Gives any two properties of ionic compounds (½ + ½ mark)
- States that Na has one valence electron, 2,8,1 (1 mark)
- Shows that Na loses it to form Na⁺ (2,8), the stable noble gas configuration (1 mark)
- OR: explains that ions cannot move in the rigid solid (1 mark)
- States that H₂ gas is liberated at the cathode (1 mark)
Revise the chapter
- Chapter: Metals and Non-metals (notes, formulas, where marks are lost and every past question)
- Topic: Ionic Compounds: Formation and Properties
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