CBSE Class 10 Science 2023: question 21(a)
Set in the CBSE Class 10 board exam of 2023, paper 31/2/1, section B, question 21(a), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q21(a) · 2 marks · Very short answerChemical Reactions and Equations
What is observed when aqueous solutions of potassium iodide and lead nitrate are mixed together ? Name the type of reaction and write the chemical equation for the reaction that occurs.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 31/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Think about which product of the ion exchange is insoluble in water and what colour it is.
Hint 2
When two compounds swap their ions, what is that type of reaction called?
Hint 3
The products are lead iodide and potassium nitrate. Balance the iodide and nitrate ions.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Observation: A yellow precipitate forms as soon as the two colourless solutions are mixed. This precipitate is lead iodide, .
- ½ mark
Type of reaction: This is a double displacement reaction, and because an insoluble solid forms it is also a precipitation reaction. The two compounds exchange their ions.
- 1 mark
Balanced equation:
Answer: Yellow precipitate of PbI₂; double displacement (precipitation) reaction; Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃
Where the marks are
- States that a yellow precipitate of lead iodide forms (½ mark)
- Names the reaction as double displacement or precipitation (½ mark)
- Writes the correct balanced equation (1 mark)
Revise the chapter
- Chapter: Chemical Reactions and Equations (notes, formulas, where marks are lost and every past question)
More questions from Chemical Reactions and Equations
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