CBSE Class 10 Science 2023: question 3
Set in the CBSE Class 10 board exam of 2023, paper 31/1/1, section A, question 3, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q3 · 1 mark · MCQChemical Reactions and Equations
In order to balance the above chemical equation, the values of , y and z respectively are :
- (A)6, 2, 2
- (B)4, 1, 2
- (C)4, 2, 1
- (D)2, 2, 1
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 31/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Start with the oxygen atoms, which appear only in and water.
Hint 2
Once the number of water molecules is fixed, the hydrogen atoms tell you how much HCl is needed.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Balance O first. There are 2 O on the left, so (). Then there are 4 H on the right, so ().
Cl: there are 4 on the left. On the right, has 2, so must supply the other 2, giving .
- 1 mark
Balanced equation: , so , which is option (C).
Answer: x = 4, y = 2, z = 1; option (C)
Where the marks are
- Correct values 4, 2, 1, option (C) (1 mark)
Revise the chapter
- Chapter: Chemical Reactions and Equations (notes, formulas, where marks are lost and every past question)
- Topic: Balancing Chemical Equations
More questions from Chemical Reactions and Equations
- 2023 board paper, set 31/2/1, Q3 · 1 markIn order to balance the following chemical equation, the values of the coefficients x and y respectively are :…
- Sample paper 2026-27, Q29(A) · 5 marksAttempt either option A or B. A. I. Refer to the dialogue between Alisha, Drishti and Bhushan in the chemistry…
- 2026 board paper, set 31/3/1, Q19 · 1 markIn the following equation x\ KI + H_2O_2 → I_2 + y\ KOH x and y respectively are :
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.