CBSE Class 10 Mathematics Basic 2026: question 34(b)
Set in the CBSE Class 10 board exam of 2026, paper 430/5/1, section D, question 34(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q34(b) · 5 marks · Long answerQuadratic Equations
A train covers a distance of 90 km at a uniform speed. Had the speed been 15 km/h more, it would have taken 30 minutes less for the same journey. Find the original speed of the train.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Time = distance ÷ speed; write the time taken at x km/h and at (x + 15) km/h.
Hint 2
Convert 30 minutes to hours and set the difference of the two times equal to it.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 2 marks
Let the original speed be km/h. Time at original speed h, at increased speed h. Difference is 30 min h:
- 2 marks
- 1 mark
or (rejected, speed cannot be negative). Original speed = 45 km/h.
Answer: Original speed = 45 km/h
Where the marks are
- Forms the time equation (2 marks)
- Reduces to (2 marks)
- Solves, rejects −60, speed 45 km/h (1 mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.