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MathsCBSE Class 10 · Standard · Board exam 2024, set 30/4/1 · 5 marks · Long answer

CBSE Class 10 Mathematics Standard 2024: question 34(a)

Set in the CBSE Class 10 board exam of 2024, paper 30/4/1, section D, question 34(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.

Q34(a) · 5 marks · Long answerCompetency-basedQuadratic Equations

A train travels a distance of 90 km at a constant speed. Had the speed been 15 km/h more, it would have taken 30 minutes less for the journey. Find the original speed of the train.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Write the time taken at each speed using time = distance ÷ speed.

Hint 2

The difference of the two times is 30 minutes = 1/2 hour; simplify to a quadratic.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let the original speed be km/h; the increased speed is km/h.

    ½ mark
  2. Time = distance/speed, and 30 minutes = h:

    1½ marks
  3. 1 mark
  4. 1 mark
  5. or . Speed cannot be negative, so . The original speed of the train is 45 km/h.

    1 mark

Answer: 45 km/h

Where the marks are

  • Takes original speed x and new speed x + 15 (½ mark)
  • Forms 90/x − 90/(x+15) = 1/2 (1½ marks)
  • Reduces to x² + 15x − 2700 = 0 (1 mark)
  • Factorises (x + 60)(x − 45) = 0 (1 mark)
  • Rejects −60, speed = 45 km/h (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.