CBSE Class 10 Mathematics Basic 2026: question 27
Set in the CBSE Class 10 board exam of 2026, paper 430/5/1, section C, question 27, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q27 · 3 marks · Short answerCoordinate Geometry
Points P(6, 0), Q(2, 8) and R(-2, 4) are vertices of PQR. It is given that MN QR such that . Using distance formula and ratio formula, show that .
Figure in the paper: Triangle PQR with P(6, 0) at the top, Q(2, 8) at bottom left and R(-2, 4) at bottom right. Point M lies on side PQ and point N lies on side PR, with MN drawn parallel to QR (arrows on MN and QR). See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Since MN ∥ QR, N divides PR in the same ratio as M divides PQ (Basic Proportionality Theorem).
Hint 2
Apply the section formula with ratio 1 : 3 starting from P, then use the distance formula for MN and QR.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
, so by BPT ; M and N divide PQ and PR in ratio .
- ½ mark
- ½ mark
- ½ mark
- ½ mark
- ½ mark
. Hence shown.
Answer: M(5, 2), N(4, 1), MN = , QR = , so
Where the marks are
- Uses BPT: (½ mark)
- M = (5, 2) by section formula (½ mark)
- N = (4, 1) by section formula (½ mark)
- MN = (½ mark)
- QR = (½ mark)
- Concludes ratio (½ mark)
Revise the chapter
- Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
- Topic: Section Formula (Internal Division)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.