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MathsCBSE Class 10 · Basic · Board exam 2026, set 430/5/1 · 3 marks · Short answer

CBSE Class 10 Mathematics Basic 2026: question 27

Set in the CBSE Class 10 board exam of 2026, paper 430/5/1, section C, question 27, for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q27 · 3 marks · Short answerCoordinate Geometry

Points P(6, 0), Q(2, 8) and R(-2, 4) are vertices of PQR. It is given that MN QR such that . Using distance formula and ratio formula, show that .

Figure in the paper: Triangle PQR with P(6, 0) at the top, Q(2, 8) at bottom left and R(-2, 4) at bottom right. Point M lies on side PQ and point N lies on side PR, with MN drawn parallel to QR (arrows on MN and QR). See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/5/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Since MN ∥ QR, N divides PR in the same ratio as M divides PQ (Basic Proportionality Theorem).

Hint 2

Apply the section formula with ratio 1 : 3 starting from P, then use the distance formula for MN and QR.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. , so by BPT ; M and N divide PQ and PR in ratio .

    ½ mark
  2. ½ mark
  3. ½ mark
  4. ½ mark
  5. ½ mark
  6. . Hence shown.

    ½ mark

Answer: M(5, 2), N(4, 1), MN = , QR = , so

Where the marks are

  • Uses BPT: (½ mark)
  • M = (5, 2) by section formula (½ mark)
  • N = (4, 1) by section formula (½ mark)
  • MN = (½ mark)
  • QR = (½ mark)
  • Concludes ratio (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.