CBSE Class 10 Mathematics Basic 2026: question 26
Set in the CBSE Class 10 board exam of 2026, paper 430/4/1, section C, question 26, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q26 · 3 marks · Short answerCircles
Prove that a parallelogram circumscribing a circle, is a rhombus.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Mark the points where the circle touches each side.
Hint 2
From each vertex, two tangents are drawn to the circle; they are equal.
Hint 3
Add all four equalities and use the fact that opposite sides of a parallelogram are equal.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Figure: parallelogram ABCD with a circle inside touching AB at P, BC at Q, CD at R and DA at S. Given: ABCD is a parallelogram circumscribing the circle. To prove: ABCD is a rhombus.
- 1 mark
Tangents from an external point are equal: , , , .
- 1 mark
Adding: , i.e. , so .
- ½ mark
In a parallelogram and , so . Adjacent sides are equal, so all four sides are equal; hence ABCD is a rhombus.
Answer: AB = BC = CD = DA, so ABCD is a rhombus.
Where the marks are
- Correct labelled figure (½ mark)
- Writes the four pairs of equal tangents (1 mark)
- Adds to get (1 mark)
- Uses opposite sides equal to conclude , rhombus (½ mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
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