CBSE Class 10 Mathematics Basic 2026: question 23
Set in the CBSE Class 10 board exam of 2026, paper 430/2/1, section B, question 23, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q23 · 2 marks · Very short answerCircles
Prove that the tangent drawn at any point of the circle is perpendicular to the radius through the point of contact.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 430/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Take a point on the tangent other than the point of contact and join it to the centre.
Hint 2
Where does this point lie relative to the circle? Compare its distance from O with the radius.
Hint 3
Which segment from a point to a line is the shortest?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Figure: circle with centre O, line touching it at A, radius OA drawn, and another point B on joined to O. Given: is the tangent at A. To prove: .
- ½ mark
Proof: Take any point B on other than A and join OB.
- ½ mark
Since a tangent meets the circle at only one point, B lies outside the circle, so radius, i.e. .
- ½ mark
Thus OA is the shortest of all segments from O to points of . The shortest distance from a point to a line is the perpendicular, so . Hence proved.
Answer: OA is the shortest distance from O to the tangent, hence OA ⟂ tangent.
Where the marks are
- Correct figure with given/to prove (½ mark)
- Takes another point B on the tangent (½ mark)
- Shows B outside the circle so OB > OA (½ mark)
- Concludes OA ⟂ l since perpendicular is the shortest distance (½ mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
- Topic: Tangent Perpendicular to Radius Theorem
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