CBSE Class 10 Mathematics Standard 2025: question 14
Set in the CBSE Class 10 board exam of 2025, paper 30/5/1, section A, question 14, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q14 · 1 mark · MCQCircles
In the adjoining figure, the sum of radii of two concentric circles is 16 cm. The length of chord AB which touches the inner circle at P is 16 cm. The difference of the radii of the given circles is
- (A)8 cm
- (B)4 cm
- (C)2 cm
- (D)3 cm
Figure in the paper: Two concentric circles with centre O. Chord AB of the outer circle touches the inner circle at P, with P lying on the chord between A and B; A and B are at the ends of the chord on the outer circle. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Triangle OPA is right-angled at P.
Hint 2
Factor .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
OP ⟂ AB [tangent ⟂ radius], so P bisects AB: . With outer, inner: .
- 1 mark
cm. Option (B).
Answer: 4 cm, option (B)
Where the marks are
- Uses and factorises to get 4 cm (1 mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
- Topic: Tangent Perpendicular to Radius Theorem
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.