MathsCBSE Class 10 · Standard · Board exam 2026, set 30/4/1 · 3 marks · Short answer

CBSE Class 10 Mathematics Standard 2026: question 26(b)

Set in the CBSE Class 10 board exam of 2026, paper 30/4/1, section C, question 26(b), for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q26(b) · 3 marks · Short answerPair of Linear Equations in Two Variables

Solve the linear equations $3 x + y = 14$ and $y = 2$ graphically.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Make a table of at least two or three points for each equation.

Hint 2

$y = 2$ is a horizontal line; find where the other line crosses it.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

For $3 x + y = 14$ , i.e. $y = 14 - 3 x$ : table of values $x = 3, y = 5$ ; $x = 4, y = 2$ ; $x = 5, y = - 1$ . Plot $(3, 5)$ , $(4, 2)$ , $(5, - 1)$ and join them to get a straight line.
1½ marks
$y = 2$ is a straight line parallel to the x-axis through $(0, 2)$ . Points: $(0, 2)$ , $(2, 2)$ , $(4, 2)$ . Draw it on the same axes.
½ mark
The two lines intersect at $(4, 2)$ . Hence the solution is $x = 4$ , $y = 2$ .
1 mark

Answer: $x = 4$ , $y = 2$

Where the marks are

Correct table and graph of $3 x + y = 14$ (1½ marks)
Correct graph of $y = 2$ (½ mark)
Reads the intersection point: $x = 4, y = 2$ (1 mark)

Revise the chapter

Chapter: Pair of Linear Equations in Two Variables (notes, formulas, where marks are lost and every past question)

Practise this chapterBoard-style questions from Pair of Linear Equations in Two Variables, one at a time, marked against the answer key and marking points.Back to the full paper2026 board paper, set 30/4/1 (Standard): every question, by section.

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CBSE Class 10 Mathematics Standard 2026: question 26(b)

Hints

Step-by-step solution

Revise the chapter

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