CBSE Class 10 Mathematics Standard 2026: question 33(b)
Set in the CBSE Class 10 board exam of 2026, paper 30/2/1, section D, question 33(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q33(b) · 5 marks · Long answerQuadratic Equations
The area of a right-angled triangle is . If the base of the triangle exceeds the altitude by 10 cm, find all the three dimensions of the triangle.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Take the altitude as x; then the base is x + 10.
Hint 2
Use area = ½ × base × altitude, solve the quadratic, then use Pythagoras for the third side.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1½ marks
Let the altitude be x cm, so base = (x + 10) cm. Area:
- 1 mark
- 1 mark
or
- ½ mark
Length cannot be negative, so ; altitude = 30 cm
- ½ mark
Base cm
- ½ mark
Hypotenuse cm [Pythagoras theorem]
Answer: Altitude = 30 cm, base = 40 cm, hypotenuse = 50 cm
Where the marks are
- Forms (1½ marks)
- Gets (1 mark)
- Factorises correctly (1 mark)
- Altitude 30 cm, rejecting −40 (½ mark)
- Base 40 cm (½ mark)
- Hypotenuse 50 cm (½ mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
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