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MathsCBSE Class 10 · Standard · Board exam 2026, set 30/3/1 · 3 marks · Short answer

CBSE Class 10 Mathematics Standard 2026: question 29

Set in the CBSE Class 10 board exam of 2026, paper 30/3/1, section C, question 29, for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q29 · 3 marks · Short answerQuadratic Equations

Find two consecutive negative integers, sum of whose squares is 481.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/3/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Let the integers be x and x + 1 and write the sum of their squares.

Hint 2

You get a quadratic. Look for two numbers with product −240 and difference 1, and keep only the root that gives negative integers.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let the two consecutive negative integers be and .
    Given:

    1 mark
  2. ½ mark
  3. Splitting the middle term:
    or

    1 mark
  4. The integers must be negative, so is rejected and .
    Required integers: and .
    (Check: .)

    ½ mark

Answer: −16 and −15

Where the marks are

  • Forms the equation (1 mark)
  • Reduces it to (½ mark)
  • Factorises to get x = −16 or 15 (1 mark)
  • Rejects 15 and states the integers −16, −15 (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.