MathsCBSE Class 10 · Standard · Board exam 2026, set 30/1/1 · 1 mark · MCQ

CBSE Class 10 Mathematics Standard 2026: question 15

Set in the CBSE Class 10 board exam of 2026, paper 30/1/1, section A, question 15, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q15 · 1 mark · MCQAreas Related to Circles

The hour hand of a clock is 7 cm long. The angle swept by it between 7:00 a.m. and 8:10 a.m. is :

(A) $(\frac{35}{4})^{\circ}$
(B) $(\frac{35}{2})^{\circ}$
(C) $3 5^{\circ}$
(D) $7 0^{\circ}$

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

The hour hand moves 360° in 12 hours.

Hint 2

Count the minutes between the two times.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

The hour hand turns $3 0^{\circ}$ in 60 minutes, which is $\frac{1}{2}^{\circ}$ per minute.
From 7:00 to 8:10 is 70 minutes, so the angle swept $= 70 \times \frac{1}{2} = 3 5^{\circ}$ . Option (c).
1 mark

Answer: $3 5^{\circ}$ , option (c)

Where the marks are

Gets 70 min × 0.5° = 35°, option (c) (1 mark)

Revise the chapter

Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)

Practise this chapterBoard-style questions from Areas Related to Circles, one at a time, marked against the answer key and marking points.Back to the full paper2026 board paper, set 30/1/1 (Standard): every question, by section.

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CBSE Class 10 Mathematics Standard 2026: question 15

Hints

Step-by-step solution

Revise the chapter

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