The HCF of 960 and 432 is : (A) 48 (B) 54 (C) 72 (D) 36

MathsCBSE Class 10 · Standard · Board exam 2026, set 30/1/1 · 1 mark · MCQ

CBSE Class 10 Mathematics Standard 2026: question 1

Set in the CBSE Class 10 board exam of 2026, paper 30/1/1, section A, question 1, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q1 · 1 mark · MCQReal Numbers

The HCF of 960 and 432 is :

(A)48
(B)54
(C)72
(D)36

Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Write both numbers as products of primes.

Hint 2

Take each common prime with its lowest power and multiply.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Prime factorisation: $960 = 2^{6} \times 3 \times 5$ and $432 = 2^{4} \times 3^{3}$ .
HCF = product of the smallest powers of the common primes $= 2^{4} \times 3 = 16 \times 3 = 48$ . So option (a) is correct.
1 mark

Answer: 48, option (a)

Where the marks are

Selects 48, option (a) (1 mark)

Revise the chapter

Chapter: Real Numbers (notes, formulas, where marks are lost and every past question)
Topic: HCF and LCM by Prime Factorisation

Practise this chapterBoard-style questions from Real Numbers, one at a time, marked against the answer key and marking points.Back to the full paper2026 board paper, set 30/1/1 (Standard): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Standard 2026: question 1

Hints

Step-by-step solution

Revise the chapter

More questions from Real Numbers