CBSE Class 10 Mathematics Standard 2026: question 24(b)
Set in the CBSE Class 10 board exam of 2026, paper 30/4/1, section B, question 24(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q24(b) · 2 marks · Very short answerReal Numbers
If the HCF of 210 and 55 is expressed as , then find the value of m.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2026 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
First find the HCF of 210 and 55 by prime factorisation.
Hint 2
Set the HCF equal to and solve for m.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
and , so HCF.
- ½ mark
So , i.e. .
- ½ mark
.
Answer:
Where the marks are
- Finds HCF = 5 by prime factorisation (1 mark)
- Forms (½ mark)
- Gets (½ mark)
Revise the chapter
- Chapter: Real Numbers (notes, formulas, where marks are lost and every past question)
- Topic: HCF and LCM by Prime Factorisation
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.