MathsCBSE Class 10 · Standard · Sample paper, session 2026-27 · 1 mark · MCQ

CBSE Class 10 Mathematics Standard sample paper 2026-27: question 10

From the official CBSE sample question paper for 2026-27, section A, question 10, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q10 · 1 mark · MCQCompetency-basedAreas Related to Circles

The diameter of a car wheel is 21 cm. The number of complete revolutions it will make in moving 66 km is:

(A) $1 0^{4}$
(B) $1 0^{5}$
(C) $1 0^{6}$
(D) $1 0^{7}$

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.

Hints

Open one hint at a time and try again before the next.

Hint 1

One revolution covers one circumference.

Hint 2

Convert km to cm before dividing.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Circumference $= π d = \frac{22}{7} \times 21 = 66$ cm. This is the distance covered in one revolution.
$66$ km $= 66 \times 1 0^{5}$ cm. Number of revolutions $= \frac{66 \times 1 0 ^{5}}{66} = 1 0^{5}$ , which is option (B).
1 mark

Answer: $1 0^{5}$ , option (B)

Where the marks are

Finds circumference 66 cm and divides 66 × 10⁵ cm by it to get 10⁵ (1 mark)

Revise the chapter

Chapter: Areas Related to Circles (notes, formulas, where marks are lost and every past question)

Practise this chapterBoard-style questions from Areas Related to Circles, one at a time, marked against the answer key and marking points.Back to the full paperSample paper 2026-27 (Standard): every question, by section.

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CBSE Class 10 Mathematics Standard sample paper 2026-27: question 10

Hints

Step-by-step solution

Revise the chapter

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