MathsCBSE Class 10 · Standard · Sample paper, session 2026-27 · 1 mark · MCQ

CBSE Class 10 Mathematics Standard sample paper 2026-27: question 1

From the official CBSE sample question paper for 2026-27, section A, question 1, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q1 · 1 mark · MCQReal Numbers

The greatest number which divides both 134 and 188, leaving remainders 4 and 6 respectively, is:

(A)13
(B)26
(C)39
(D)65

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.

Hints

Open one hint at a time and try again before the next.

Hint 1

What does the number divide exactly once the remainders are taken away?

Hint 2

Find the HCF of 130 and 182.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Remove the remainders. The required number must exactly divide $134 - 4 = 130$ and $188 - 6 = 182$ .
$130 = 2 \times 5 \times 13$ and $182 = 2 \times 7 \times 13$ , so $HCF (130, 182) = 2 \times 13 = 26$ .
1 mark
The greatest such number is 26, which is option (B).

Answer: 26, option (B)

Where the marks are

Subtracts the remainders and finds HCF(130, 182) = 26 (1 mark)

Revise the chapter

Chapter: Real Numbers (notes, formulas, where marks are lost and every past question)
Topic: HCF and LCM by Prime Factorisation

Practise this chapterBoard-style questions from Real Numbers, one at a time, marked against the answer key and marking points.Back to the full paperSample paper 2026-27 (Standard): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Standard sample paper 2026-27: question 1

Hints

Step-by-step solution

Revise the chapter

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