CBSE Class 10 Mathematics Basic sample paper 2026-27: question 33(A)
From the official CBSE sample question paper for 2026-27, section D, question 33(A), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q33(A) · 5 marks · Long answerCompetency-basedQuadratic Equations
A train travels a distance of 360 km at a uniform speed. If the speed had been 5 km/h more, then it would have taken 1 hour less to cover the same distance. Find the speed of the train.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.
Hints
Open one hint at a time and try again before the next.
Hint 1
Write the time taken at speed and at speed ; their difference is 1 hour.
Hint 2
Clear the denominators to get a quadratic, then reject the negative root.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Let the uniform speed of the train be km/h; the increased speed is km/h.
- 1 mark
Time = distance ÷ speed, so
- 1 mark
- 1 mark
- 1 mark
or
- ½ mark
Speed cannot be negative, so . The speed of the train is 40 km/h.
Answer: 40 km/h
Where the marks are
- Defines the speed variable (½ mark)
- Forms the time equation (1 mark)
- Simplifies to (1 mark)
- Applies the quadratic formula or factorisation (1 mark)
- Gets roots 40 and −45 (1 mark)
- Rejects the negative root; speed = 40 km/h (½ mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
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