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MathsCBSE Class 10 · Basic · Sample paper, session 2026-27 · 5 marks · Long answer

CBSE Class 10 Mathematics Basic sample paper 2026-27: question 33(B)

From the official CBSE sample question paper for 2026-27, section D, question 33(B), for 5 marks. Try it first; the hints and our step-by-step solution are below.

Q33(B) · 5 marks · Long answerQuadratic Equations

John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. Find the number of marbles they had with them in the beginning.

Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2026-27.

Hints

Open one hint at a time and try again before the next.

Hint 1

If John has marbles, Jivanti has . Subtract 5 from each.

Hint 2

Multiply the new counts, set the product equal to 124 and solve the quadratic; both roots are valid.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let John have marbles at the beginning; then Jivanti had .

    ½ mark
  2. After losing 5 each, they have and marbles, so

    1 mark
  3. ½ mark
  4. 1 mark
  5. or

    1 mark
  6. Case 1: , so John had 36 and Jivanti had .

    ½ mark
  7. Case 2: , so John had 9 and Jivanti had 36.

    ½ mark

Answer: 36 and 9 marbles (John 36, Jivanti 9, or John 9, Jivanti 36)

Where the marks are

  • Defines the variables (½ mark)
  • Forms (1 mark)
  • Gets (½ mark)
  • Applies the quadratic formula correctly (1 mark)
  • Gets roots 36 and 9 (1 mark)
  • Case 1 interpretation (½ mark)
  • Case 2 interpretation (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.