One of the zeroes of the polynomial p(x) = kx² - 9x + 3 is (-3/2 ). The value of k is: (A) 22/3 (B) -14/3 (C) 14/3 (D) -22/3

MathsCBSE Class 10 · Basic · Board exam 2025, set 430/4/1 · 1 mark · MCQ

CBSE Class 10 Mathematics Basic 2025: question 4

Set in the CBSE Class 10 board exam of 2025, paper 430/4/1, section A, question 4, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q4 · 1 mark · MCQPolynomials

One of the zeroes of the polynomial $p (x) = k x^{2} - 9 x + 3$ is $(- \frac{3}{2})$ . The value of $k$ is:

(A) $\frac{22}{3}$
(B) $- \frac{14}{3}$
(C) $\frac{14}{3}$
(D) $- \frac{22}{3}$

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

A zero of a polynomial makes its value equal to 0.

Hint 2

Substitute $x = - \frac{3}{2}$ into $p (x)$ and solve the resulting equation in k.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Put $x = - \frac{3}{2}$ in $p (x)$ and set it to zero: $p (- \frac{3}{2}) = \frac{9}{4} k + \frac{27}{2} + 3 = 0$ .
½ mark
So $\frac{9}{4} k = - \frac{33}{2}$ , which gives $k = - \frac{66}{9} = - \frac{22}{3}$ . Hence option (D).
½ mark

Answer: $k = - \frac{22}{3}$ , option (D)

Where the marks are

Substitutes the zero and equates $p (- \frac{3}{2})$ to 0 (½ mark)
Solves to get $k = - \frac{22}{3}$ (½ mark)

Revise the chapter

Chapter: Polynomials (notes, formulas, where marks are lost and every past question)

Practise this chapterBoard-style questions from Polynomials, one at a time, marked against the answer key and marking points.Back to the full paper2025 board paper, set 430/4/1 (Basic): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Basic 2025: question 4

Hints

Step-by-step solution

Revise the chapter

More questions from Polynomials