CBSE Class 10 Mathematics Standard 2025: question 27
Set in the CBSE Class 10 board exam of 2025, paper 30/5/1, section C, question 27, for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q27 · 3 marks · Short answerPolynomials
Obtain the zeroes of the polynomial . Hence, write a polynomial each of whose zeroes is twice the zeroes of given polynomial.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/5/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Split 18x into two terms whose coefficients multiply to .
Hint 2
Double each zero, then find their sum and product.
Hint 3
A quadratic with known sum S and product P is .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Split the middle term: . So the zeroes are and .
- ½ mark
Twice the zeroes: and
- ½ mark
Sum of the new zeroes
- ½ mark
Product of the new zeroes
- ½ mark
Required polynomial , or (or any non-zero multiple of it).
Answer: Zeroes are and ; required polynomial
Where the marks are
- Factorises and finds the zeroes , (1 mark)
- Writes the new zeroes , (½ mark)
- Sum (½ mark)
- Product (½ mark)
- Forms the polynomial (½ mark)
Revise the chapter
- Chapter: Polynomials (notes, formulas, where marks are lost and every past question)
More questions from Polynomials
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- 2025 board paper, set 430/4/1 (Basic), Q4 · 1 markOne of the zeroes of the polynomial p(x) = kx² - 9x + 3 is (-3/2 ). The value of k is:
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.