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MathsCBSE Class 10 · Basic · Board exam 2025, set 430/4/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Basic 2025: question 23(b)

Set in the CBSE Class 10 board exam of 2025, paper 430/4/1, section B, question 23(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q23(b) · 2 marks · Very short answerProbability

A die is thrown twice. What is the probability that (i) difference between two numbers obtained is 3? (ii) sum of the numbers obtained is 8?

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

How many outcomes are possible when a die is thrown twice?

Hint 2

Write the outcomes as ordered pairs (first throw, second throw), and remember that (1, 4) and (4, 1) are different outcomes.

Hint 3

Count the pairs that satisfy each condition and divide by the total.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. A die thrown twice gives equally likely outcomes.

  2. (i) Outcomes with difference 3: , which is 6 outcomes. P(difference is 3)

    1 mark
  3. (ii) Outcomes with sum 8: , which is 5 outcomes. P(sum is 8)

    1 mark

Answer: (i) ; (ii)

Where the marks are

  • Lists the 6 favourable outcomes and gets (1 mark)
  • Lists the 5 favourable outcomes and gets (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.