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MathsCBSE Class 10 · Basic · Board exam 2025, set 430/3/1 · 5 marks · Long answer

CBSE Class 10 Mathematics Basic 2025: question 32(a)

Set in the CBSE Class 10 board exam of 2025, paper 430/3/1, section D, question 32(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.

Q32(a) · 5 marks · Long answerQuadratic Equations

Find two consecutive odd integers, sum of whose squares is 290.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/3/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Consecutive odd integers differ by 2, so take them as x and x + 2.

Hint 2

Form the equation from the sum of squares, simplify, and factorise; look for two numbers with product −143 and sum 2.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let the two consecutive odd integers be and .

    ½ mark
  2. According to the question:

    1½ marks
  3. 1½ marks
  4. or

    1 mark
  5. The required integers are 11 and 13. Check: . (The root gives the pair , which also works.)

    ½ mark

Answer: 11 and 13 (also −13 and −11)

Where the marks are

  • Takes the integers as x and x + 2 (½ mark)
  • Forms (1½ marks)
  • Simplifies to (1½ marks)
  • Solves to get x = 11 (1 mark)
  • States the integers 11 and 13 (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.