CBSE Class 10 Mathematics Basic 2025: question 35(a)
Set in the CBSE Class 10 board exam of 2025, paper 430/2/1, section D, question 35(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q35(a) · 5 marks · Long answerStatistics
The lengths of 40 leaves of a plant are measured, correct to the nearest millimetre and data obtained is represented in the following table: Length in (mm) 100-120: 8; 120-140: 9; 140-160: 12; 160-180: 5; 180-200: 6. Find the median length (in mm) of the leaves.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Build a cumulative frequency column and find N/2.
Hint 2
The median class is the first class whose cumulative frequency exceeds N/2.
Hint 3
Use Median = l + ((N/2 − cf)/f) × h with cf of the class before.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 2 marks
Cumulative frequency table: 100–120: f = 8, cf = 8; 120–140: f = 9, cf = 17; 140–160: f = 12, cf = 29; 160–180: f = 5, cf = 34; 180–200: f = 6, cf = 40. .
- 2 marks
, which lies in cf 29, so median class is 140–160: . Median .
- 1 mark
. The median length of the leaves is 145 mm.
Answer: Median length = 145 mm
Where the marks are
- Correct cumulative frequency table (2 marks)
- Identifies median class and substitutes in the median formula (2 marks)
- Median = 145 mm (1 mark)
Revise the chapter
- Chapter: Statistics (notes, formulas, where marks are lost and every past question)
- Topic: Median of Grouped Data
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.