CBSE Class 10 Mathematics Basic 2024: question 15
Set in the CBSE Class 10 board exam of 2024, paper 430/4/1, section A, question 15, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q15 · 1 mark · MCQStatistics
The median group in the following frequency distribution is :
| Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 | 50 – 60 |
|---|---|---|---|---|---|---|
| Frequency | 5 | 8 | 20 | 15 | 7 | 5 |
- (A)10 – 20
- (B)20 – 30
- (C)30 – 40
- (D)40 – 50
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Find the total frequency N and then N/2.
Hint 2
Make the cumulative frequency column.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
, so . The cumulative frequencies are 5, 13, 33, …
- 1 mark
The first cumulative frequency greater than 30 is 33, so the median class is 20–30, option (B).
Answer: 20 – 30, option (B)
Where the marks are
- Uses N/2 = 30 and cumulative frequency to find the median class 20–30 (1 mark)
Revise the chapter
- Chapter: Statistics (notes, formulas, where marks are lost and every past question)
- Topic: Median of Grouped Data
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.