CBSE Class 10 Mathematics Basic 2025: question 22(b)
Set in the CBSE Class 10 board exam of 2025, paper 430/1/1, section B, question 22(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q22(b) · 2 marks · Very short answerTriangles
In the given figure, , and . Find the measures of and .
Figure in the paper: Two parallel horizontal lines: S and R on the upper line (SR), P and Q on the lower line (PQ). Segments SQ and RP cross at O. Angle at R between RS and RO marked 70°. Angle ROQ = 125° marked at O on the right side. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
lies outside and stands on the straight line SQ.
Hint 2
An exterior angle equals the sum of the two interior opposite angles. Then match the vertices of the similar triangles in order.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
SOQ is a straight line, so is an exterior angle of . Then [exterior angle property], so , giving .
- ½ mark
Since with , we get [corresponding angles of similar triangles].
- ½ mark
.
Answer: ∠OSR = 55°, ∠OQP = 55°
Where the marks are
- Uses the exterior angle property to get (1 mark)
- States that corresponding angles of similar triangles are equal (½ mark)
- Concludes (½ mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.