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MathsCBSE Class 10 · Basic · Board exam 2025, set 430/1/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Basic 2025: question 22(b)

Set in the CBSE Class 10 board exam of 2025, paper 430/1/1, section B, question 22(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q22(b) · 2 marks · Very short answerTriangles

In the given figure, , and . Find the measures of and .

Figure in the paper: Two parallel horizontal lines: S and R on the upper line (SR), P and Q on the lower line (PQ). Segments SQ and RP cross at O. Angle at R between RS and RO marked 70°. Angle ROQ = 125° marked at O on the right side. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

lies outside and stands on the straight line SQ.

Hint 2

An exterior angle equals the sum of the two interior opposite angles. Then match the vertices of the similar triangles in order.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. SOQ is a straight line, so is an exterior angle of . Then [exterior angle property], so , giving .

    1 mark
  2. Since with , we get [corresponding angles of similar triangles].

    ½ mark
  3. .

    ½ mark

Answer: ∠OSR = 55°, ∠OQP = 55°

Where the marks are

  • Uses the exterior angle property to get (1 mark)
  • States that corresponding angles of similar triangles are equal (½ mark)
  • Concludes (½ mark)

Revise the chapter

  • Chapter: Triangles (notes, formulas, where marks are lost and every past question)

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.