CBSE Class 10 Mathematics Basic 2025: question 22(b)
Set in the CBSE Class 10 board exam of 2025, paper 430/3/1, section B, question 22(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q22(b) · 2 marks · Very short answerTriangles
In the given figure, and . Prove that .
Figure in the paper: Triangle QRT with P on side QT and S on side QR. Segment PR joins P to R, and segment PS joins P to S. Angle 2 is marked at vertex Q (between QS/QR and QP/QT) and angle 1 is marked at vertex R (between RP and RQ). See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Equal angles ∠1 and ∠2 sit in triangle PQR. What does that tell you about two of its sides?
Hint 2
Replace PR in the given ratio, then look for an angle shared by both triangles.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
In , , i.e. . Hence [sides opposite equal angles are equal].
- ½ mark
Given . Putting gives , i.e. .
- ½ mark
In and : , since this is , common to both.
- ½ mark
The sides including the equal angle are proportional, so [SAS similarity criterion].
Answer: ΔPQS ~ ΔTQR by SAS similarity
Where the marks are
- Uses ∠1 = ∠2 to get PQ = PR (½ mark)
- Replaces PR by PQ to get (½ mark)
- Notes ∠Q is common (½ mark)
- Concludes similarity by SAS (½ mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.