CBSE Class 10 Mathematics Standard 2025: question 24
Set in the CBSE Class 10 board exam of 2025, paper 30/6/1, section B, question 24, for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q24 · 2 marks · Very short answerTriangles
P is a point on the side BC of such that . Prove that .
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/6/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Look for two triangles that both contain side AC and angle C.
Hint 2
Compare and : one angle is given equal, angle C is common.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Figure: with P on BC, AP joined; and marked equal.
- 1 mark
In and : (given) and (common). So [AA similarity].
- ½ mark
Corresponding sides are proportional: . Hence proved.
Answer: (proved)
Where the marks are
- Correct figure (½ mark)
- Proves by AA (1 mark)
- Writes proportion and concludes (½ mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Problems on Similar Triangles
More questions from Triangles
- Sample paper 2024-25 (Standard), Q26(A) · 3 marksIn △ ABC, D, E and F are midpoints of BC, CA and AB respectively. Prove that △ FBD ~ △ DEF and △ DEF ~ △ ABC.
- 2024 board paper, set 30/3/1 (Standard), Q24 · 2 marksIn the given figure, EAEC = EBED, prove that △ EAB ~ △ ECD.
- 2023 board paper, set 30/4/1 (Standard), Q33(A) · 5 marksD is a point on the side BC of a triangle ABC such that ∠ ADC = ∠ BAC, prove that CA² = CB.CD
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.