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MathsCBSE Class 10 · Standard · Board exam 2025, set 30/4/1 · 5 marks · Long answer

CBSE Class 10 Mathematics Standard 2025: question 34

Set in the CBSE Class 10 board exam of 2025, paper 30/4/1, section D, question 34, for 5 marks. Try it first; the hints and our step-by-step solution are below.

Q34 · 5 marks · Long answerCompetency-basedSurface Areas and Volumes

A wooden cubical die is formed by forming hemispherical depressions on each face of the cube such that face 1 has one depression, face 2 has two depressions and so on. The sum of number of hemispherical depressions on opposite faces is always 7. If the edge of the cubical die measures 5 cm and each hemispherical depression is of diameter 1.4 cm, find the total surface area of the die so formed.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Count the depressions on all six faces: 1 to 6.

Hint 2

Each depression removes a flat circle from the cube's surface but adds a curved surface .

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Number of depressions . Radius of each cm.

    1 mark
  2. TSA of die = TSA of cube + CSA of 21 hemispheres − area of 21 circular openings.
    TSA of cube cm²

    1 mark
  3. CSA of 21 hemispheres cm²

    1 mark
  4. Area of 21 circular bases removed cm²

    1 mark
  5. TSA cm²

    1 mark

Answer: 182.34 cm²

Where the marks are

  • Total depressions = 21 (1 mark)
  • TSA of cube = 150 cm² (1 mark)
  • CSA of 21 hemispheres = 64.68 cm² (1 mark)
  • Base area of 21 depressions = 32.34 cm² (1 mark)
  • Total surface area 182.34 cm² (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.