CBSE Class 10 Mathematics Standard 2025: question 34
Set in the CBSE Class 10 board exam of 2025, paper 30/4/1, section D, question 34, for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q34 · 5 marks · Long answerCompetency-basedSurface Areas and Volumes
A wooden cubical die is formed by forming hemispherical depressions on each face of the cube such that face 1 has one depression, face 2 has two depressions and so on. The sum of number of hemispherical depressions on opposite faces is always 7. If the edge of the cubical die measures 5 cm and each hemispherical depression is of diameter 1.4 cm, find the total surface area of the die so formed.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Count the depressions on all six faces: 1 to 6.
Hint 2
Each depression removes a flat circle from the cube's surface but adds a curved surface .
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Number of depressions . Radius of each cm.
- 1 mark
TSA of die = TSA of cube + CSA of 21 hemispheres − area of 21 circular openings.
TSA of cube cm² - 1 mark
CSA of 21 hemispheres cm²
- 1 mark
Area of 21 circular bases removed cm²
- 1 mark
TSA cm²
Answer: 182.34 cm²
Where the marks are
- Total depressions = 21 (1 mark)
- TSA of cube = 150 cm² (1 mark)
- CSA of 21 hemispheres = 64.68 cm² (1 mark)
- Base area of 21 depressions = 32.34 cm² (1 mark)
- Total surface area 182.34 cm² (1 mark)
Revise the chapter
- Chapter: Surface Areas and Volumes (notes, formulas, where marks are lost and every past question)
- Topic: Surface Area and Volume Formulae Revision
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