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MathsCBSE Class 10 · Standard · Board exam 2025, set 30/4/1 · 3 marks · Short answer

CBSE Class 10 Mathematics Standard 2025: question 31

Set in the CBSE Class 10 board exam of 2025, paper 30/4/1, section C, question 31, for 3 marks. Try it first; the hints and our step-by-step solution are below.

Q31 · 3 marks · Short answerCircles

Rectangle ABCD circumscribes the circle of radius 10 cm. Prove that ABCD is a square. Hence, find the perimeter of ABCD.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/4/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Tangents from a point outside a circle to it are equal in length.

Hint 2

Add the four tangent equalities, then use opposite sides of a rectangle are equal.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Figure: rectangle ABCD with a circle (centre O, radius 10 cm) touching AB at P, BC at Q, CD at R and DA at S.

    ½ mark
  2. Tangents drawn from an external point are equal: , , , .

    1 mark
  3. Adding: ...(i)

    ½ mark
  4. In rectangle ABCD, and , so (i) gives . A rectangle with adjacent sides equal is a square, so ABCD is a square.

    ½ mark
  5. Side of square = distance between opposite tangent points = diameter cm. Perimeter cm.

    ½ mark

Answer: ABCD is a square; perimeter = 80 cm

Where the marks are

  • Correct figure (½ mark)
  • Equal tangent lengths from each vertex (1 mark)
  • Adds to get (½ mark)
  • Uses rectangle property to get , hence square (½ mark)
  • Side = 20 cm, perimeter = 80 cm (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.