CBSE Class 10 Mathematics Basic 2025: question 9
Set in the CBSE Class 10 board exam of 2025, paper 430/1/1, section A, question 9, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q9 · 1 mark · MCQCircles
In the given figure, PA is a tangent to a circle with centre O. If OP = 10 cm, then the length of AP is :
- (A) cm
- (B)20 cm
- (C)5 cm
- (D) cm
Figure in the paper: Circle with centre O; P outside the circle; PA is a tangent touching the circle at A. OA is a radius. Angle APO = 30°. OP = 10 cm is marked along the line from O to P. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 430/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
What angle does a tangent make with the radius at the point of contact?
Hint 2
In the right triangle, OP is the hypotenuse and AP is the side next to the 30° angle.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
[tangent ⟂ radius at the point of contact].
- 1 mark
In right : , so cm. The answer is option (D).
Answer: 5√3 cm, option (D)
Where the marks are
- Uses ∠OAP = 90° and cos 30° to get AP = 5√3 cm (1 mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
- Topic: Tangent and Secant of a Circle
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.