CBSE Class 10 Mathematics Standard 2025: question 4
Set in the CBSE Class 10 board exam of 2025, paper 30/2/1, section A, question 4, for 1 mark. Try it first; the hints and our step-by-step solution are below.
Q4 · 1 mark · MCQReal Numbers
The least number which is a perfect square and is divisible by each of , and , is :
- (A)
- (B)
- (C)
- (D)
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Any number divisible by 16, 20 and 50 must be a multiple of their LCM.
Hint 2
Find the LCM using prime factorisation, then check whether its prime powers are all even.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Factorise: , , . So .
- ½ mark
is already a perfect square. So the least such number is , which is not among the options. Of the options, only is a perfect square divisible by all three numbers, but it is not the least.
Answer: 400 (no option is correct)
Where the marks are
- Finds the LCM as 400 and notes that it is a perfect square, so no option is correct. The board gives the 1 mark for any attempt (1 mark)
Revise the chapter
- Chapter: Real Numbers (notes, formulas, where marks are lost and every past question)
- Topic: HCF and LCM by Prime Factorisation
More questions from Real Numbers
- 2025 board paper, set 30/2/1 (Standard), Q18 · 1 markThe HCF of 40, 110 and 360 is :
- 2025 board paper, set 30/3/1 (Standard), Q23(a) · 2 marksFind the smallest number which is divisible by both 644 and 462.
- 2025 board paper, set 30/3/1 (Standard), Q23(b) · 2 marksTwo numbers are in the ratio 4 : 5 and their HCF is 11. Find the LCM of these numbers.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.