CBSE Class 10 Mathematics Standard 2025: question 34(a)
Set in the CBSE Class 10 board exam of 2025, paper 30/1/1, section D, question 34(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q34(a) · 5 marks · Long answerQuadratic Equations
The perimeter of a right triangle is 60 cm and its hypotenuse is 25 cm. Find the lengths of other two sides of the triangle.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Use the perimeter to find the sum of the two unknown sides.
Hint 2
Write one side in terms of the other and apply Pythagoras theorem with hypotenuse 25 cm.
Hint 3
You should get a quadratic. Find two numbers whose product is 300 and whose sum is 35.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Let the other two sides be cm and cm.
From the perimeter: .
- ½ mark
So .
- 1 mark
By Pythagoras theorem, .
Substituting: .
- 1 mark
Expand: , so .
Dividing by 2: .
- 1 mark
Factorise: , so .
Therefore or .
- ½ mark
If , then . If , then .
Hence the other two sides are 15 cm and 20 cm.
Check: and .
Answer: The other two sides are 15 cm and 20 cm.
Where the marks are
- Writes the perimeter equation (1 mark)
- Expresses (½ mark)
- Applies Pythagoras: (1 mark)
- Simplifies to (1 mark)
- Solves to get or (1 mark)
- States the sides as 15 cm and 20 cm (½ mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
- Topic: Word Problems on Quadratic Equations
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