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MathsCBSE Class 10 · Standard · Board exam 2025, set 30/1/1 · 5 marks · Long answer

CBSE Class 10 Mathematics Standard 2025: question 34(a)

Set in the CBSE Class 10 board exam of 2025, paper 30/1/1, section D, question 34(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.

Q34(a) · 5 marks · Long answerQuadratic Equations

The perimeter of a right triangle is 60 cm and its hypotenuse is 25 cm. Find the lengths of other two sides of the triangle.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Use the perimeter to find the sum of the two unknown sides.

Hint 2

Write one side in terms of the other and apply Pythagoras theorem with hypotenuse 25 cm.

Hint 3

You should get a quadratic. Find two numbers whose product is 300 and whose sum is 35.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. Let the other two sides be cm and cm.

    From the perimeter: .

    1 mark
  2. So .

    ½ mark
  3. By Pythagoras theorem, .

    Substituting: .

    1 mark
  4. Expand: , so .

    Dividing by 2: .

    1 mark
  5. Factorise: , so .

    Therefore or .

    1 mark
  6. If , then . If , then .

    Hence the other two sides are 15 cm and 20 cm.

    Check: and .

    ½ mark

Answer: The other two sides are 15 cm and 20 cm.

Where the marks are

  • Writes the perimeter equation (1 mark)
  • Expresses (½ mark)
  • Applies Pythagoras: (1 mark)
  • Simplifies to (1 mark)
  • Solves to get or (1 mark)
  • States the sides as 15 cm and 20 cm (½ mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.