CBSE Class 10 Mathematics Standard 2025: question 33(a)
Set in the CBSE Class 10 board exam of 2025, paper 30/1/1, section D, question 33(a), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q33(a) · 5 marks · Long answerTriangles
The diagonal BD of a parallelogram ABCD intersects the line segment AE at the point F, where E is any point on the side BC. Prove that .
Source: official question paper from cbse.gov.in (PDF). See it in the full 2025 board paper, set 30/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Look for two triangles that have F as a common vertex, one containing DF and FA and the other containing FB and EF.
Hint 2
AD is parallel to BC, and BD is a transversal. Which pairs of angles at F and on BD are then equal?
Hint 3
Show , then write the ratio of their corresponding sides.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Figure: Draw parallelogram with at the bottom and at the top. Take a point on side and join . Draw diagonal so that it cuts at .
Since is a parallelogram, , so (because lies on ).
- 2 marks
In and :
- [vertically opposite angles]
- [alternate interior angles, , transversal ]
So [AA similarity criterion].
- 1 mark
Corresponding sides of similar triangles are proportional:
- 1 mark
From , cross-multiply to get . Hence proved.
Answer: (AA), so , i.e. . Proved.
Where the marks are
- Correct labelled figure of the parallelogram with E on BC, AE and BD meeting at F (1 mark)
- Proves using vertically opposite angles and alternate angles (AA), with reasons (2 marks)
- Writes the ratio of corresponding sides (1 mark)
- Cross-multiplies to reach (1 mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Problems on Similar Triangles
More questions from Triangles
- 2025 board paper, set 30/6/1 (Standard), Q24 · 2 marksP is a point on the side BC of △ ABC such that ∠ APC = ∠ BAC. Prove that AC² = BC · CP.
- Sample paper 2024-25 (Standard), Q26(A) · 3 marksIn △ ABC, D, E and F are midpoints of BC, CA and AB respectively. Prove that △ FBD ~ △ DEF and △ DEF ~ △ ABC.
- 2024 board paper, set 30/3/1 (Standard), Q24 · 2 marksIn the given figure, EAEC = EBED, prove that △ EAB ~ △ ECD.
The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.