CBSE Class 10 Mathematics Standard sample paper 2025-26: question 32
From the official CBSE sample question paper for 2025-26, section D, question 32, for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q32 · 5 marks · Long answerCompetency-basedQuadratic Equations
A train travels at a certain average speed for a distance of 63km and then travels at a distance of 72km at an average speed of 6km/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original average speed?
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2025-26.
Hints
Open one hint at a time and try again before the next.
Hint 1
Time = distance ÷ speed. Write each part's time in terms of x.
Hint 2
Add the two times and set the total equal to 3.
Hint 3
Clear the fractions, simplify to a quadratic and factorise it. Remember that speed must be positive.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Let the original average speed be km/h. Time taken for 63 km is h.
- 1 mark
The new speed is km/h, so the time for 72 km is h. Total time: .
- 1 mark
, so .
- 1 mark
, which gives , i.e. .
- 1 mark
, so and or . Speed cannot be negative, so .
Check: h ✓. The original average speed is 42 km/h.
Answer: 42 km/h
Where the marks are
- Writes the time for the first part as 63/x (1 mark)
- Writes the time for the second part as 72/(x+6) and uses total = 3 h (1 mark)
- Forms the equation (1 mark)
- Reduces it to (1 mark)
- Solves it, rejects −3 and states 42 km/h (1 mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
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