CBSE Class 10 Mathematics Basic 2024: question 23(b)
Set in the CBSE Class 10 board exam of 2024, paper 430/4/1, section B, question 23(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.
Q23(b) · 2 marks · Very short answerTriangles
In the given figure, and . Prove that .
Figure in the paper: Quadrilateral ABCD with diagonal AC. Point L lies on AC. M lies on side AB and N lies on side AD. LM is drawn parallel to CB and LN parallel to CD (arrow marks). See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Diagonal AC splits the figure into two triangles, each containing one of the parallel lines.
Hint 2
Apply the Basic Proportionality Theorem in △ABC and in △ADC. Both give a ratio involving AL/AC.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 0.75 marks
In , , so by the Basic Proportionality Theorem, ...(i)
- 0.75 marks
In , , so by BPT, ...(ii)
- ½ mark
From (i) and (ii), . Hence proved.
Answer: AM/AB = AL/AC = AN/AD, hence AM/AB = AN/AD.
Where the marks are
- Applies BPT in △ABC to get AM/AB = AL/AC, and in △ADC to get AN/AD = AL/AC (1½ marks)
- Equates the two ratios to conclude AM/AB = AN/AD (½ mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Basic Proportionality Theorem (Thales Theorem)
More questions from Triangles
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.