CBSE Class 10 Mathematics Basic 2024: question 33(b)
Set in the CBSE Class 10 board exam of 2024, paper 430/3/1, section D, question 33(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q33(b) · 5 marks · Long answerCircles
Prove that the parallelogram circumscribing a circle is a rhombus. Also, find area of the rhombus, if radius of circle is cm and length of one side of the rhombus is cm.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 430/3/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Use: lengths of tangents drawn from an external point to a circle are equal.
Hint 2
Add the four equalities and group them into the sides of the parallelogram.
Hint 3
For area, the radius to each point of contact is the height of a triangle with a side of the rhombus as base.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
Figure: Parallelogram ABCD circumscribes a circle with centre O, touching AB, BC, CD, DA at P, Q, R, S respectively; OA, OB and OP are joined.
- 1 mark
Tangents from an external point are equal: , , , .
- ½ mark
Adding:
- ½ mark
- 1 mark
In a parallelogram and , so . Adjacent sides equal, hence ABCD is a rhombus.
- 1 mark
[tangent ⟂ radius], cm. The four triangles AOB, BOC, COD, DOA each have base 10 cm and height 3 cm. Area of rhombus cm²
Answer: ABCD is a rhombus; area = 60 cm²
Where the marks are
- Correct labelled figure (1 mark)
- Equal tangent lengths from each vertex (1 mark)
- Adding the equalities (½ mark)
- (½ mark)
- Using opposite sides equal to get , so rhombus (1 mark)
- Area cm² (1 mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
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