CBSE Class 10 Mathematics Basic 2024: question 24

Hints

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Step-by-step solution

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1. Any point on the Y-axis has x-coordinate 0. Let $P(0,y)$ divide $AB$ in the ratio $k:1$.

   ½ mark

2. By the section formula, x-coordinate of $P=\frac{k(-1)+1(5)}{k+1}=0\Rightarrow -k+5=0\Rightarrow k=5$. Required ratio is $5:1$.

   1 mark

3. $y=\frac{5(-4)+1(-6)}{5+1}=\frac{-26}{6}=-\frac{13}{3}$. So the point of intersection is $\left(0,-\frac{13}{3}\right)$.

   ½ mark

Answer: Ratio $5:1$; point $\left(0,-\frac{13}{3}\right)$

Revise the chapter

• Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
• Topic: Section Formula (Internal Division)