MathsCBSE Class 10 · Basic · Board exam 2023, set 430/2/1 · 1 mark · MCQ

CBSE Class 10 Mathematics Basic 2023: question 2

Set in the CBSE Class 10 board exam of 2023, paper 430/2/1, section A, question 2, for 1 mark. Try it first; the hints and our step-by-step solution are below.

Q2 · 1 mark · MCQCoordinate Geometry

In what ratio does x-axis divide the line segment joining the points $A (2, - 3)$ and $B (5, 6)$ ?

(A) $2 : 3$
(B) $2 : 1$
(C) $3 : 4$
(D) $1 : 2$

Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/2/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

Any point on the x-axis has y-coordinate 0.

Hint 2

Take the ratio as $k : 1$ and use the section formula for the y-coordinate.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Let the x-axis divide AB in the ratio $k : 1$ . On the x-axis the y-coordinate is 0, so $\frac{6 k - 3}{k + 1} = 0$ .
$6 k = 3 \Rightarrow k = \frac{1}{2}$ . The ratio is $1 : 2$ , option (D).
1 mark

Answer: 1 : 2, option (D)

Where the marks are

Sets the y-coordinate of the section point to 0 and gets $1 : 2$ (1 mark)

Revise the chapter

Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
Topic: Section Formula (Internal Division)

Practise this chapterBoard-style questions from Coordinate Geometry, one at a time, marked against the answer key and marking points.Back to the full paper2023 board paper, set 430/2/1 (Basic): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Basic 2023: question 2

Hints

Step-by-step solution

Revise the chapter

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