CBSE Class 10 Mathematics Standard 2024: question 27(a)
Set in the CBSE Class 10 board exam of 2024, paper 30/4/1, section C, question 27(a), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q27(a) · 3 marks · Short answerProbability
Three coins are tossed simultaneously. What is the probability of getting
- (i)1 mark
at least one head ?
- (ii)1 mark
exactly two tails ?
- (iii)1 mark
at most one tail ?
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/4/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
List all 8 possible outcomes of tossing three coins.
Hint 2
'At most one tail' means zero tails or one tail; count those outcomes.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Outcomes: HHH, HHT, HTH, THH, HTT, THT, TTH, TTT — total 8.
- 1 mark
(i) At least one head: all except TTT, so 7 outcomes.
- 1 mark
(ii) Exactly two tails: HTT, THT, TTH — 3 outcomes.
- 1 mark
(iii) At most one tail: HHH, HHT, HTH, THH — 4 outcomes.
Answer: (i) 7/8; (ii) 3/8; (iii) 1/2
Where the marks are
- P(at least one head) = 7/8 (1 mark)
- P(exactly two tails) = 3/8 (1 mark)
- P(at most one tail) = 4/8 = 1/2 (1 mark)
Revise the chapter
- Chapter: Probability (notes, formulas, where marks are lost and every past question)
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