MathsCBSE Class 10 · Standard · Board exam 2024, set 30/2/1 · 2 marks · Very short answer

CBSE Class 10 Mathematics Standard 2024: question 25(b)

Set in the CBSE Class 10 board exam of 2024, paper 30/2/1, section B, question 25(b), for 2 marks. Try it first; the hints and our step-by-step solution are below.

Q25(b) · 2 marks · Very short answerCoordinate Geometry

$A (3, 0)$ , $B (6, 4)$ and $C (- 1, 3)$ are vertices of a triangle $A B C$ . Find length of its median $B E$ .

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/2/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

A median from B goes to the mid-point of the opposite side AC.

Hint 2

Find E by the mid-point formula, then use the distance formula.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

Median $B E$ joins $B$ to the mid-point $E$ of $A C$ : $E = (\frac{3 + ( - 1 )}{2}, \frac{0 + 3}{2}) = (1, \frac{3}{2})$ .
1 mark
$B E = (6 - 1)^{2} + (4 - \frac{3}{2})^{2} = 25 + \frac{25}{4} = \frac{125}{4} = \frac{5 5}{2}$ units.
1 mark

Answer: $B E = \frac{5 5}{2}$ units $(= 125/4)$

Where the marks are

Mid-point E of AC is $(1, 3/2)$ (1 mark)
Distance BE $= \frac{5 5}{2}$ (1 mark)

Revise the chapter

Chapter: Coordinate Geometry (notes, formulas, where marks are lost and every past question)
Topic: Distance Formula

Practise this chapterBoard-style questions from Coordinate Geometry, one at a time, marked against the answer key and marking points.Back to the full paper2024 board paper, set 30/2/1 (Standard): every question, by section.

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.

CBSE Class 10 Mathematics Standard 2024: question 25(b)

Hints

Step-by-step solution

Revise the chapter

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