CBSE Class 10 Mathematics Standard 2024: question 36
Set in the CBSE Class 10 board exam of 2024, paper 30/1/1, section E, question 36, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q36 · 4 marks · Case-basedCompetency-basedQuadratic Equations
A rectangular floor area can be completely tiled with 200 square tiles. If the side length of each tile is increased by 1 unit, it would take only 128 tiles to cover the floor.
(Figure: photograph of a floor covered with grey rectangular tiles.)
- (i)1 mark
Assuming the original length of each side of a tile be units, make a quadratic equation from the above information.
- (ii)1 mark
Write the corresponding quadratic equation in standard form.
- (iii)2 marks
(a) Find the value of , the length of side of a tile, by factorisation.
OR
(iii)2 marks(b) Solve the quadratic equation for , using quadratic formula.
Figure in the paper: Photograph of a floor laid with grey rectangular tiles in a staggered pattern. See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/1/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
The floor area stays the same: number of tiles × area of one tile.
Hint 2
Equate 200x² with 128(x+1)², then divide by 8 to simplify.
Hint 3
For factorising, find two numbers with product −144 and sum −32. Reject any negative length.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
(i) Area of one original tile , so floor area .
New side , so floor area .
The floor is the same, so:
- 1 mark
(ii) Divide both sides by 8:
- 1 mark
(iii)(a) Split the middle term ():
- 1 mark
(iii)(a) So or .
A length cannot be negative, so units.
- 1 mark
(iii)(b) For : , , .
- 1 mark
(iii)(b) So or .
Since a length cannot be negative, units.
Answer: (i) 200x² = 128(x+1)²; (ii) 9x² − 32x − 16 = 0; (iii)(a) x = 4 units; (iii)(b) x = 4 units (rejecting −4/9)
Where the marks are
- (i) Equates the two floor areas: (1 mark)
- (ii) Simplifies to (1 mark)
- (iii)(a) Factorises as (1 mark)
- (iii)(a) Rejects the negative root and gets (1 mark)
- (iii)(b) Substitutes correctly in the quadratic formula: (1 mark)
- (iii)(b) Gets , rejecting (1 mark)
Revise the chapter
- Chapter: Quadratic Equations (notes, formulas, where marks are lost and every past question)
- Topic: Word Problems on Quadratic Equations
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.