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MathsCBSE Class 10 · Standard · Board exam 2024, set 30/1/1 · 4 marks · Case-based

CBSE Class 10 Mathematics Standard 2024: question 36

Set in the CBSE Class 10 board exam of 2024, paper 30/1/1, section E, question 36, for 4 marks. Try it first; the hints and our step-by-step solution are below.

Q36 · 4 marks · Case-basedCompetency-basedQuadratic Equations

A rectangular floor area can be completely tiled with 200 square tiles. If the side length of each tile is increased by 1 unit, it would take only 128 tiles to cover the floor.

(Figure: photograph of a floor covered with grey rectangular tiles.)

  1. (i)

    Assuming the original length of each side of a tile be units, make a quadratic equation from the above information.

    1 mark
  2. (ii)

    Write the corresponding quadratic equation in standard form.

    1 mark
  3. (iii)

    (a) Find the value of , the length of side of a tile, by factorisation.

    2 marks
  4. OR

    (iii)

    (b) Solve the quadratic equation for , using quadratic formula.

    2 marks

Figure in the paper: Photograph of a floor laid with grey rectangular tiles in a staggered pattern. See it in the official paper.

Source: official question paper from cbse.gov.in (PDF). See it in the full 2024 board paper, set 30/1/1.

Hints

Open one hint at a time and try again before the next.

Hint 1

The floor area stays the same: number of tiles × area of one tile.

Hint 2

Equate 200x² with 128(x+1)², then divide by 8 to simplify.

Hint 3

For factorising, find two numbers with product −144 and sum −32. Reject any negative length.

Step-by-step solution

Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.

  1. (i) Area of one original tile , so floor area .

    New side , so floor area .

    The floor is the same, so:

    1 mark
  2. (ii) Divide both sides by 8:

    1 mark
  3. (iii)(a) Split the middle term ():

    1 mark
  4. (iii)(a) So or .

    A length cannot be negative, so units.

    1 mark
  5. (iii)(b) For : , , .

    1 mark
  6. (iii)(b) So or .

    Since a length cannot be negative, units.

    1 mark

Answer: (i) 200x² = 128(x+1)²; (ii) 9x² − 32x − 16 = 0; (iii)(a) x = 4 units; (iii)(b) x = 4 units (rejecting −4/9)

Where the marks are

  • (i) Equates the two floor areas: (1 mark)
  • (ii) Simplifies to (1 mark)
  • (iii)(a) Factorises as (1 mark)
  • (iii)(a) Rejects the negative root and gets (1 mark)
  • (iii)(b) Substitutes correctly in the quadratic formula: (1 mark)
  • (iii)(b) Gets , rejecting (1 mark)

Revise the chapter

The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.