CBSE Class 10 Mathematics Basic sample paper 2024-25: question 38
From the official CBSE sample question paper for 2024-25, section E, question 38, for 4 marks. Try it first; the hints and our step-by-step solution are below.
Q38 · 4 marks · Case-basedCompetency-basedSurface Areas and Volumes
Rinku was very happy to receive a fancy jumbo pencil from his best friend Rohan on his birthday. Pencil is a basic writing tool, when sharpened its shape is a combination of cylinder & cone as given in the picture.
Cylindrical pencil with conical head is a common shape worldwide since ages. Commonly pencils are made up of wood & plastic but we should promote pencils made up of eco-friendly material (many options available in the market these days) to save environment.
The dimensions of Rinku's pencil are given as follows: Length of cylindrical portion is 21cm. Diameter of the base is 1 cm and height of the conical portion is 1.2 cm.
Based on the above information, answer the following questions:
- (i)1 mark
Find the slant height of the sharpened part.
- (ii)1 mark
Find curved surface area of sharpened part (in terms of ).
- (iii)2 marks
(A) Find the total surface area of the pencil (in terms of ).
OR
(iii)2 marks(B) The pencil's total height decreases by 8.2 cm after sharpening it many times, what is the volume of the cylindrical part of the shortened pencil (in terms of )?
Figure in the paper: A photograph of a jumbo pencil with a cylindrical body and a sharpened conical tip at one end. Dimensions given in text: cylindrical portion length 21 cm, base diameter 1 cm, conical portion height 1.2 cm. See it in the official paper.
Source: official sample paper from cbseacademic.nic.in (PDF). See it in the full Sample paper 2024-25.
Hints
Open one hint at a time and try again before the next.
Hint 1
The radius is half the diameter. Height, radius and slant height of the cone form a right triangle.
Hint 2
The curved surface of a cone is πrl and the curved surface of a cylinder is 2πrH.
Hint 3
The surface of the pencil has three parts: the cylinder's side, the cone's side and one flat circular end. For (B), only the cylindrical length changes.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
Given: radius cm, cone height cm, cylinder length cm.
- ½ mark
(i) Slant height: .
- ½ mark
(i) cm.
- ½ mark
(ii) Curved surface area of the cone: .
- ½ mark
(ii) This gives cm².
- ½ mark
(iii)(a) TSA of pencil = CSA of cylinder + CSA of cone + area of the flat circular base .
- 1 mark
(iii)(a) Substitute: .
- ½ mark
(iii)(a) TSA cm².
- ½ mark
(iii)(b) The conical tip stays the same after sharpening, so the cylindrical part shortens by 8.2 cm. New length cm.
- 1 mark
(iii)(b) Volume of the cylinder: .
- ½ mark
(iii)(b) This gives cm³.
Answer: (i) 1.3 cm; (ii) 0.65π cm²; (iii)(A) 21.9π cm²; (iii)(B) 3.2π cm³
Where the marks are
- Uses with the correct values (½ mark)
- Gets cm (½ mark)
- Uses for the cone (½ mark)
- Gets cm² (½ mark)
- (iii)(A): writes TSA as cylinder CSA + cone CSA + base area (½ mark)
- (iii)(A): substitutes correctly, with cylinder CSA (1 mark)
- (iii)(A): gets cm² (½ mark)
- (iii)(B): finds the new cylinder length 12.8 cm (½ mark)
- (iii)(B): substitutes into (1 mark)
- (iii)(B): gets cm³ (½ mark)
Revise the chapter
- Chapter: Surface Areas and Volumes (notes, formulas, where marks are lost and every past question)
- Topic: Surface Area of a Combination of Solids
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.