CBSE Class 10 Mathematics Basic 2023: question 35(b)
Set in the CBSE Class 10 board exam of 2023, paper 430/6/1, section D, question 35(b), for 5 marks. Try it first; the hints and our step-by-step solution are below.
Q35(b) · 5 marks · Long answerTriangles
In the given figure, and . Prove that PQS TQR.
Figure in the paper: Triangle QTR with vertex T at the top and base QR. Point P lies on side QT and point S lies on base QR, with PS and PR joined. Angle 1 is marked at Q (between QP and QS) and angle 2 is marked at R (between RS/RP region near base). Points are labelled Q (bottom left), R (bottom right), S (on base), T (top), P (on QT). See it in the official paper.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/6/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
What does tell you about the sides of ?
Hint 2
Replace PR by PQ in the given ratio, then flip both sides.
Hint 3
Angle Q is common to both triangles. Which sides enclose it in each triangle?
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- 1 mark
In , , i.e. .
So [sides opposite equal angles are equal]. - 2 marks
Given . Taking reciprocals gives .
Since , this becomes ...(i) - 1½ marks
In and :
- [common angle Q]
- [from (i)]
- ½ mark
So [SAS similarity criterion]. Proved.
Answer: by SAS similarity.
Where the marks are
- Uses to get (1 mark)
- Rearranges the given ratio and substitutes PR = PQ to get (2 marks)
- Identifies the common angle Q and the proportional sides (1½ marks)
- Concludes similarity by SAS (½ mark)
Revise the chapter
- Chapter: Triangles (notes, formulas, where marks are lost and every past question)
- Topic: Problems on Similar Triangles
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The question is transcribed from the official paper; figures are described in words. The solution, hints and chapter tag are ours. Spotted an error? Write tosupport@questionbuddy.in.