CBSE Class 10 Mathematics Basic 2023: question 28(b)
Set in the CBSE Class 10 board exam of 2023, paper 430/2/1, section C, question 28(b), for 3 marks. Try it first; the hints and our step-by-step solution are below.
Q28(b) · 3 marks · Short answerCircles
Prove that the parallelogram circumscribing a circle is a rhombus.
Source: official question paper from cbse.gov.in (PDF). See it in the full 2023 board paper, set 430/2/1.
Hints
Open one hint at a time and try again before the next.
Hint 1
Mark the four points where the sides touch the circle.
Hint 2
Each vertex is an external point from which two tangents are drawn. What do you know about their lengths?
Hint 3
Add the four tangent equalities, then use the fact that opposite sides of a parallelogram are equal.
Step-by-step solution
Each step shows the marks it earns, as an examiner would award them. Checked by an independent re-solve from the question paper.
- ½ mark
Figure: Draw parallelogram ABCD with all four sides touching a circle. The points of contact are P on AB, Q on BC, R on CD and S on DA.
Given: ABCD is a parallelogram circumscribing the circle.
To prove: ABCD is a rhombus.
- 1 mark
Tangents drawn from an external point to a circle are equal in length. So:
- ½ mark
Adding these four equations:
- ½ mark
In a parallelogram opposite sides are equal: and .
So , which gives .
- ½ mark
Therefore . A parallelogram with all sides equal is a rhombus, so ABCD is a rhombus. Hence proved.
Answer: AB + CD = AD + BC together with AB = CD and BC = AD gives AB = BC = CD = DA, so ABCD is a rhombus
Where the marks are
- Correct labelled figure (1/2 mark)
- Writes the four equal-tangent relations (1 mark)
- Adds them to get (1/2 mark)
- Uses the opposite sides of the parallelogram to get (1/2 mark)
- Concludes all sides are equal, so ABCD is a rhombus (1/2 mark)
Revise the chapter
- Chapter: Circles (notes, formulas, where marks are lost and every past question)
- Topic: Solving Problems Using Tangent Properties
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